A=1/2(B^1+B^2)

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Solution for A=1/2(B^1+B^2) equation: 


x in (-oo:+oo)

A = (1/2)*(B^2+B^1) // - (1/2)*(B^2+B^1)

A-((1/2)*(B^2+B^1)) = 0

(-1/2)*(B^2+B)+A = 0

A-1/2*(B^2+B) = 0

A-1/2*(B^2+B) = 0

A-1/2*B^2-1/2*B = 0

A-1/2*B^2-1/2*B = 0

x belongs to the empty set

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